Q. In an hydrogen atom, the electron revolves around the nucleus in an orbit of radius $0.53 \times 10^{- 10}\ m.$ Then the electrical potential produced by the nucleus at the position of the electron is
A) $- 13.6\ V$
B) $- 27.2\ V$
C) $27.2\ V$
D) $13.6\ V$
Explanation
(c) $V = 9 \times 10^{9} \times \frac{Q}{r} = 9 \times 10^{9} \times \frac{( + 1.6 \times 10^{- 19})}{0.53 \times 10^{- 10}} = 27.2V$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.