Q.
A hollow cylinder has a charge $q$ coulomb within it. If $\phi$ is the electric flux in units of $volt - meter$ associated with the curved surface $B,$ the flux linked with the plane surface $A$ in units of $volt - meter$ will be
A) $\frac{1}{2}\left( \frac{q}{\in_{0}} - \phi \right)$
B) $\frac{q}{2 \in_{0}}$
C) $\frac{\phi}{3}$
D) $\frac{q}{\in_{0}} - \phi$
Explanation
(a) $\phi_{Total} = \phi_{A} + \phi_{B} + \phi_{C} = \frac{q}{\in_{0}};$
$\because\phi_{B} = \phi$ and $\phi_{A} = \phi_{C} = \phi^{'}$ [assumed]
$\therefore 2\phi^{'} + \phi = \frac{q}{\in_{0}} \Rightarrow \phi^{'} = \frac{1}{2}\left( \frac{q}{\in_{0}} - \phi \right)$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.