Q. Let $V$ be the electric potential at a given point. Then the electric field $E_{x}$ along $x$ direction at that point is given by
A) $\int_{0}^{\infty}{Vdx}$
B) $\frac{dV}{dx}$
C) $- \frac{dV}{dx}$
D) $- V\frac{dV}{dx}$
Explanation
(c) The electric field intensity at a point in an electric field in a given direction is equal to the negative potential gradient in that direction
$\ ie,\ \ E = - \frac{dV}{dx}$
The negative sign signifies that the potential decreases in the direction of the electric field.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.