Q. A particle of mass $m$ and charge $q$ is placed at rest in a uniform electric field $E$ and then released. The kinetic energy attained by the particle after moving a distance $y$ is
A) $qEy^{2}$
B) $qE^{2}y$
C) $qEy$
D) $q^{2}Ey$
Explanation
(c) Kinetic energy = Force $\times$ Displacement = $qEy$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.