Q. Three capacitors each of capacitance $C$ and of breakdown voltage $V$ are joined in series. The capacitance and breakdown voltage of the combination will be
A) $\frac{C}{3},\frac{V}{3}$
B) $3C,\frac{V}{3}$
C) $\frac{C}{3},3V$
D) $3C,3V$
Explanation
(c) $\frac{1}{C'} = \frac{1}{C} + \frac{1}{C} + \frac{1}{C} = \frac{3}{C}$
$C^{'} = \frac{C}{3}$
$V^{'} = V_{1} + V_{2} + V_{3} = V + V + V = 3V$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.