Q. A $10pF$ capacitor is connected to a $50\ V$ battery. How much electrostatic energy is stored in the capacitor
A) $1.25 \times 10^{- 8}\ J$
B) $2.5 \times 10^{- 7}\ J$
C) $3.5 \times 10^{- 5}\ J$
D) $4.5 \times 10^{- 2}\ J$
Explanation
(a) $U = \frac{1}{2}CV^{2} = \frac{1}{2} \times 10 \times 10^{- 12} \times (50)^{2} = 1.25 \times 10^{- 8}\ J$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.