(b) $C_{1} = \frac{C}{4}$ (series); $C_{2} = 4C$ (parallel) $\therefore\frac{C_{1}}{C_{2}} = \frac{C/4}{4C} = \frac{1}{16}$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.