In the given circuit, a charge of $+ 80\ \mu C$ is given to the upper plate of the $4\ \mu F$ capacitor. Then in the steady state, the charge on the upper plate of the $3\ \mu F$ capacitor is [image:1_image191.emf]

Question

Dr. Abubacker · Accepted Answer

(c) $q_{3} = \frac{C_{3}}{C_{2} + C_{3}}.Q$
$q_{3} = \frac{3}{3 + 2} 	imes 80 = \frac{3}{5} 	imes 80$
$= 48\ \mu C$

Q. In the given circuit, a charge of $+ 80\ \mu C$ is given to the upper plate of the $4\ \mu F$ capacitor. Then in the steady state, the charge on the upper plate of the $3\ \mu F$ capacitor is

Explanation

Reviewed by Dr. Abubacker

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