Q. Three capacitors of capacity $C_{1},C_{2},C_{3}$ are connected in series. Their total capacity will be
A) $C_{1} + C_{2} + C_{3}$
B) $1/(C_{1} + C_{2} + C_{3})$
C) $\left( C_{1}^{- 1} + C_{2}^{- 1} + C_{3}^{- 1} \right)^{- 1}$
D) None of these
Explanation
(c) $\frac{1}{C_{R}} = \frac{1}{C_{1}} + \frac{1}{C_{2}} + \frac{1}{C_{3}} \Rightarrow C_{R} = \left( C_{1}^{- 1} + C_{2}^{- 1} + C_{3}^{- 1} \right)^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.