Q. Two charges $q_{1}$ and $q_{2}$ are placed in vacuum at a distance $d$ and the force acting between them is $F$. If a medium of dielectric constant 4 is introduced between them, the force now will be
A) $4F$
B) $2F$
C) $\frac{F}{2}$
D) $\frac{F}{4}$
Explanation
(d) In the pressure of medium force becomes $\frac{1}{K\ }$ times
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.