Charges $+ q\ and - q$ are placed at point $A\ and\ B$ respectively which are a distance $2L$ apart, $C$ is the midpoint between $A\ and\ B.$ The work done in moving a charge $+ Q$ along the semicircle $CRD$ is [image:1_image193.emf]

Question

Dr. Abubacker · Accepted Answer

(d) Potential at $C\ V_{C} = 0$
Potential at $D\ V_{D} = \frac{K( - q)}{L} + \frac{Kq}{3L} = - \frac{2}{3}\frac{Kq}{L}$
$	herefore$ Potential difference $V_{D} - V_{C} = - \frac{2}{3}\frac{Kq}{L}$
$\Rightarrow W = Q.\left( V_{D} - V_{C} ight) = - \frac{2}{3} 	imes \frac{1}{4\pi \in_{0}}.\frac{qQ}{L} = - \frac{qQ}{6\pi \in_{0}L}$
[image:1_image374.emf]

Q. Charges $+ q\ and - q$ are placed at point $A\ and\ B$ respectively which are a distance $2L$ apart, $C$ is the midpoint between $A\ and\ B.$ The work done in moving a charge $+ Q$ along the semicircle $CRD$ is

Explanation

Reviewed by Dr. Abubacker

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