Q. A slab of material of dielectric constant $K$ has the same area as the plates of a parallel plate capacitor but has a thickness $\left( \frac{3}{4} \right)d,$ where $d$ is the separation of the plates. The ratio of the capacitance $C$ (in the presence of the dielectric) to the capacitance $C_{0}$ (in the absence of the dielectric) is
A) $\frac{3K}{K + 4}$
B) $\frac{3}{4}K$
C) $\frac{4K}{K + 3}$
D) $\frac{4}{3}K$
Explanation
The correct answer is Option C: $\frac{4K}{K + 3}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.