Q. Four point charges $- Q,\ - q,\ 2q$ and $2Q$ are placed, one at each corner of the square. The relation between $Q$ and $q$ for which the potential at the centre of the square is zero is

A) $Q = \ - q$
B) $Q = - \frac{1}{q}$
C) $Q = q$
D) $Q = \frac{1}{q}$
Explanation

(a) [image:1_image376.emf]
Let the side length of square be $''a''$ then potential at centre $O$ is
$V = \frac{K( - Q)}{\left( \frac{a}{\sqrt{2}} \right)} + \frac{k( - q)}{\frac{a}{\sqrt{2}}} + \frac{k(2q)}{\frac{a}{\sqrt{2}}} + \frac{k(2Q)}{\frac{a}{\sqrt{2}}} = 0$
$= - Q - q + 2q + 2Q = 0 \Rightarrow Q + q = 0 \Rightarrow Q = - q$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.