(a) [image:1_image376.emf]
Let the side length of square be $''a''$ then potential at centre $O$ is
$V = \frac{K( - Q)}{\left( \frac{a}{\sqrt{2}} \right)} + \frac{k( - q)}{\frac{a}{\sqrt{2}}} + \frac{k(2q)}{\frac{a}{\sqrt{2}}} + \frac{k(2Q)}{\frac{a}{\sqrt{2}}} = 0$
$= - Q - q + 2q + 2Q = 0 \Rightarrow Q + q = 0 \Rightarrow Q = - q$