Q. A hollow conducting spherical shell of radius $R$ is charged with $Q$ coulomb. The amount of work done for moving any charge $q$ from the centre to the surface of the shell will be
A) $\frac{qQ}{4\pi\varepsilon_{0}R}$
B) Zero
C) $\frac{Qq}{\pi\varepsilon_{0}R}$
D) $\frac{Qq}{2\pi\varepsilon_{0}R}$
Explanation
(b) $W = q.\mathrm{\Delta}V$
$= q\left( V_{surface} - V_{centre} \right) = q \times \left( \frac{1}{4\pi\varepsilon_{0}} \times \frac{Q}{R} - \frac{1}{4\pi\varepsilon_{0}} \times \frac{Q}{R} \right) = 0$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.