Q. The acceleration of an electron in an electric field of magnitude $50\ V/cm,$ if $e/m$ value of the electron is $1.76 \times 10^{11}\ C/kg,$ is
A) $8.8 \times 10^{14}\ m/\sec^{2}$
B) $6.2 \times 10^{13}\ m/\sec^{2}$
C) $5.4 \times 10^{12}m/\sec^{2}$
D) Zero
Explanation
(a) $a = \frac{eE}{m} \Rightarrow a = 1.76 \times 10^{11} \times 50 \times 10^{2} = 8.8 \times 10^{14}\ m/\sec^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.