
(b) All the three plates will produce electric field at $P$ along negative $z$-axis. Hence,
$\mathbf{E}_{p} = \left\lbrack \frac{\sigma}{2\varepsilon_{0}} + \frac{2\sigma}{2\varepsilon_{0}} + \frac{\sigma}{2\varepsilon_{0}} \right\rbrack\left( - \widehat{\mathbf{k}} \right)$
$= - \frac{2\sigma}{\varepsilon_{0}}\widehat{\mathbf{k}}$