Two point charges $+ 3\mu C$ and $+ 8\mu C$ repel each other with a force of 40$N$. If a charge of $- 5\mu C$ is added to each of them, then the force between them will become

Question

Dr. Abubacker · Accepted Answer

(a) In second case, charges will be$\  - 2\mu C$ and $+ 3\mu C$
Since $F \propto Q_{1}Q_{2}\ i.e.\frac{F}{F^{'}} = \ \frac{Q_{1}Q_{2}}{Q_{1}^{'}\ Q_{2}^{'}}$
$	herefore\frac{40}{F'} = \frac{3 	imes 8}{- 2 	imes 3} = - 4 \Rightarrow F^{'} = 10N$ (Attractive)

Q. Two point charges $+ 3\mu C$ and $+ 8\mu C$ repel each other with a force of 40$N$. If a charge of $- 5\mu C$ is added to each of them, then the force between them will become

Explanation

Reviewed by Dr. Abubacker

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