Q. At a certain distance from a point charge the electric field is $500\ V/m$ and the potential is $3000\ V$. What is this distance
A) $6\ m$
B) $12\ m$
C) $36\ m$
D) $144\ m$
Explanation
(a) $V = E \times r \Rightarrow r = \frac{V}{E} = \frac{3000}{500} = 6\ m$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.