Q.
Six charges, three positive and three negative of equal magnitude are to be placed at the vertices of a regular hexagon such that the electric field at O is double the electric field when only one positive charge of same magnitude is placed at R. Which of the following arrangements of charges is possible for P, Q, R, S, T and U respectively?
A) $+ , - , + , - , - , +$
B) $+ , - , + , - , + , -$
C) $+ , + , - , + , - , -$
D) $- , + , + , - , + , -$
Explanation
(d) According to option (d) the electric field due to $P$ and $S\ $and due to $\mathcal{Q}$ and $T$ add to zero. While due to $U$ and $R$ will be added up. Hence the correct option is (d).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.