Q. The ratio of electric fields on the axis and at equator of an electric dipole will be

A) 1:1
B) 2:1
C) 4:1
D) 1:4
Explanation

(b) The electric field on the axis of a dipole of length small compared to point where electric field is to be determined is
$E_{A} = \frac{1}{4\pi\varepsilon_{0}}.\frac{2p}{r^{3}}\ \ \ \ \ \ldots\ldots\ldots\ldots(i)$
[image:1_image380.emf]
Where p is electric dipole moment.
Intensity at a point on the equatorial line of a dipole is
$E_{E} = \frac{1}{4\pi\varepsilon_{0}}.\frac{p}{r^{3}}NC^{- 1}\ \ \ \ldots.(ii)$
From Eqs. (i) and (ii), we get
$\frac{E_{A}}{E_{E}} = \frac{2p}{r^{3}} \times \frac{r^{3}}{p} = \frac{2}{1}$
[image:1_image381.emf]

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.