(d) $E_{axial} = E_{equatorial} \Rightarrow k.\frac{2p}{x^{3}} = \frac{k.p}{y^{3}} \Rightarrow \frac{x}{y} = \frac{2^{1/3}}{1} = \sqrt[3]{2}:1$
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Ph.D. in Physics with 19+ years of teaching experience.