A $500\mu F$ capacitor is charged at a steady rate of $100\mu C/second.$ The potential difference across the capacitor will be $10\ V$ after an interval of

Question

Dr. Abubacker · Accepted Answer

(d) Charge on capacitor for when it’s potential becomes $10\ V$
$Q = CV = 500 	imes 10^{- 6} 	imes 10 = 5000 	imes 10^{- 6}\mu C$
$	herefore$ Required time $= \frac{5000 	imes 10^{- 6}}{100 	imes 10^{- 6}} = 50\ \sec$

Q. A $500\mu F$ capacitor is charged at a steady rate of $100\mu C/second.$ The potential difference across the capacitor will be $10\ V$ after an interval of

Explanation

Reviewed by Dr. Abubacker

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