Q. When air is replaced by a dielectric medium of constant $k$, the maximum force of attraction between two charges separated by a distance
A) Decreases $k$ times
B) Remains unchanged
C) Increases $k$ times
D) Increases $k^{- 1}$ times
Explanation
(a) $F^{'} = \ \frac{1}{4\pi\varepsilon_{0}K}\frac{q_{1}q_{2}}{r^{2}} = \frac{F}{K\ }$
If $F$ is the force in air, then $F'$ is less than $F$ since $K > 1$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.