Q. A $10\ \mu F$ capacitor is charged to a potential difference of $1000\ V.$ The terminals of the charged capacitor are disconnected from the power supply and connected to the terminals of an uncharged $6\mu F$ capacitor. What is the final potential difference across each capacitor
A) $167\ V$
B) $100\ V$
C) $625\ V$
D) $250\ V$
Explanation
(c) Common potential $V = \frac{C_{1}V_{1}}{C_{1} + C_{2}} = \frac{10^{- 2}}{16 \times 10^{- 6}} = 625V$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.