Q. Three condensers each of capacitance $2F$ are put in series. The resultant capacitance is
A) $6F$
B) $\frac{3}{2}F$
C) $\frac{2}{3}F$
D) $5F$
Explanation
(c) $\frac{1}{C} = \frac{1}{2} + \frac{1}{2} + \frac{1}{2} \Rightarrow C = \frac{2}{3}F$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.