Two capacitors $C_{1}$ and $C_{2} = 2C_{1}$ are connected in a circuit with a switch between them as shown in the figure. Initially the switch is open and $C_{1}$ holds charge $Q.$ The switch is closed. At steady state, the charge on each capacitor will be [image:1_image212.emf]

Question

Dr. Abubacker · Accepted Answer

(b) In steady state charge on $C_{1}$ is
$Q_{1} = \left( \frac{C_{1}}{C_{1} + C_{2}} ight) 	imes Q = \frac{Q}{3}$
and charge on $C_{2}$ is $Q_{2} = \left( \frac{C_{2}}{C_{1} + C_{2}} ight).Q = \frac{2}{3}Q$

Q. Two capacitors $C_{1}$ and $C_{2} = 2C_{1}$ are connected in a circuit with a switch between them as shown in the figure. Initially the switch is open and $C_{1}$ holds charge $Q.$ The switch is closed. At steady state, the charge on each capacitor will be

Explanation

Reviewed by Dr. Abubacker

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