Q.
Two capacitor $A\ $and $B$ are connected in series with a battery as shown in the figure. When the switch $S$ is closed and the two capacitors get charged fully, then
A) The potential difference across the plates of $A$ is $4V$ and across the plates of $B$ is $6V$
B) The potential difference across the plates of $A$ is $6V$ and across the plates of $B$ is $4V$
C) The ratio of electrical energies stored in $A$ and $B$ is $2\ :3$
D) The ratio of charges on $A$ and $B$ is $3\ :2$
Explanation
(b) In series combination of capacitors, voltage distributes on them, in the reverse ratio of their capacitance $i.e.$
$\frac{V_{A}}{V_{B}} = \frac{3}{2}$ …(i)
Also $V_{A} + V_{B} = 10$ …(ii)
On solving (i) and (ii) $V_{A} = 6V,\ V_{B} = 4V$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.