Q. A parallel plate condenser is filled with two dielectrics as shown. Area of each plate is $A\ metre^{2}$ and the separation is $t\ metre.$ The dielectric constants are $k_{1}$ and $k_{2}$ respectively. Its capacitance in farad will be
A) $\frac{\varepsilon_{0}A}{t}\ (k_{1} + k_{2})$
B) $\frac{\varepsilon_{0}A}{t}\ .\frac{k_{1} + k_{2}}{2}$
C) $\frac{{2\varepsilon}_{0}A}{t}\ (k_{1} + k_{2})$
D) $\frac{\varepsilon_{0}A}{t}\ .\frac{k_{1} - k_{2}}{2}$
Explanation
(b) The two capacitors are in parallel so $C = \frac{\varepsilon_{0}A}{t \times 2}(k_{1} + k_{2})$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.