Q. A spherical conductor of radius $2m$ is charged to a potential of $120\ V.$ It is now placed inside another hollow spherical conductor of radius $6m.$ Calculate the potential to which the bigger sphere would be raised
A) $20\ V$
B) $60\ V$
C) $80\ V$
D) $40\ V$
Explanation
(d) If charge acquired by the smaller sphere is $Q$ then it’s
potential $120 = \frac{kQ}{2}$ …(i)
Whole charge comes to outer sphere
Also potential of the outer sphere
$V = \frac{kQ}{6}$ …(ii)
From equation (i) and (ii) $V = 40\ volt$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.