Q. On increasing the plate separation of a charged condenser, the energy
A) Increases
B) Decreases
C) Remains unchanged
D) Becomes zero
Explanation
(a) Energy $U = \frac{1}{2}\frac{Q^{2}}{C}$ for a charged capacitor charge $Q$ is costant and with the increase in separation $C$ will decrease $\left( C \propto \frac{1}{d} \right),$ so overall $U$ will increase
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.