Q. When the $10^{19}$ electrons are removed from a neutral metal plate, the electric charge on it is
A) $- 1.6\ C$
B) $+ \ 1.6\ C$
C) $10^{+ 19}\ C$
D) $10^{- 19}C$
Explanation
(b) By using $Q = ne \Rightarrow Q = 10^{19} \times 1.6 \times 10^{- 19} = + 1.6\ C$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.