Q. A parallel plate air capacitor is charged to a potential difference of $V.$ After disconnecting the battery, distance between the plates of the capacitor is increased using an insulating handle. As a result, the potential difference between the plates
A) Decreases
B) Increases
C) Becomes zero
D) Does not change
Explanation
(b) $V = \frac{Q}{C} = \frac{Qd}{\varepsilon_{0}KA} \Rightarrow V \propto d$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.