Q. A bullet of mass $2\ gm$ is having a charge of $2\mu C.$ Through what potential difference must it be accelerated, starting from rest, to acquire a speed of $10\ m/s$
A) $5\ kV$
B) $50\ kV$
C) $5\ V$
D) $50\ V$
Explanation
(b) By using $\frac{1}{2}mv^{2} = QV$
$\Rightarrow \frac{1}{2} \times 2 \times 10^{- 3} \times (10)^{2} = 2 \times 10^{- 6}V \Rightarrow V = 50\ kV$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.