(d) $\frac{q}{t} = 10^{10} \times 1.6 \times 10^{- 19}$ and $q = 1C$ So, $\frac{1}{t} = 1.6 \times 10^{- 9}$ $t = \frac{10^{10}}{16}sec \Rightarrow t =$ 20 years
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Ph.D. in Physics with 19+ years of teaching experience.