Q. $N$ identical drops of mercury are charged simultaneously to 10 volt. When combined to form one large drop, the potential is found to be 40 volt, the value of $N$ is
A) 4
B) 6
C) 8
D) 10
Explanation
(c) $V = N^{2/3}V \Rightarrow 40 = N^{2/3} \times 10$
$N^{2/3} = 4 \Rightarrow N^{2} = 64 \Rightarrow N = 8$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.