A pendulum bob of mass $30.7 imes 10^{- 6}kg$ and carrying a charge $2 imes 10^{- 8}C$ is at rest in a horizontal uniform electric field of $20000\ V/m$. The tension in the thread of the pendulum is $(g = 9.8m/s^{2})$

Question

A pendulum bob of mass $30.7 	imes 10^{- 6}kg$ and carrying a charge $2 	imes 10^{- 8}C$ is at rest in a horizontal uniform electric field of $20000\ V/m$. The tension in the thread of the pendulum is $(g = 9.8m/s^{2})$

Dr. Abubacker · Accepted Answer

(c) $T = \sqrt{(mg)^{2} + (QE)^{2}}$
$= \sqrt{\left( 30.7 	imes 10^{- 6} 	imes 9.8 ight)^{2} + \left( 2 	imes 10^{- 8} 	imes 20000 ight)^{2}} = 5 	imes 10^{- 4}N$

Q. A pendulum bob of mass $30.7 \times 10^{- 6}kg$ and carrying a charge $2 \times 10^{- 8}C$ is at rest in a horizontal uniform electric field of $20000\ V/m$. The tension in the thread of the pendulum is $(g = 9.8m/s^{2})$

Explanation

Reviewed by Dr. Abubacker

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