Q. Two metallic spheres of radii $1\ cm$ and $2cm$ are given charges $10^{- 2}\ C$ and$\ 5 \times 10^{- 2}C$ respectively. If they are connected by a conducting wire, the final charge on the smaller sphere is
A) $3 \times 10^{- 2}C$
B) $1 \times 10^{- 2}C$
C) $4 \times 10^{- 2}C$
D) $2 \times 10^{- 2}C$
Explanation
(d) $Q_{1} = 10^{- 2}C,\ Q_{2} = 5 \times 10^{- 2}C$
Total charge of the system $Q = 6 \times 10^{- 2}\ C$
Charge on small sphere
$Q_{1}^{'} = \frac{Qr_{1}}{r_{1} + r_{2}} = \frac{6 \times 10^{- 2} \times 1}{1 + 2} = 2 \times 10^{- 2}C$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.