Q. The dimension of (1/2) $\varepsilon_{0}E^{2}$ ($\varepsilon_{0}\ :$ permittivity of free space$;E:$ electric field) is
A) $MLT^{- 1}$
B) $ML^{2}T^{- 2}$
C) $ML^{- 1}T^{- 2}$
D) $ML^{2}T^{- 1}$
Explanation
(c) Energy density $= \frac{Energy}{Volume}$ so it’s dimensions are
$\frac{ML^{2}T^{- 2}}{L^{3}} = \lbrack ML^{- 1}T^{- 2}\rbrack$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.