The magnetic potential at a point on the axial line of a bar magnet of dipole moment M is V. What is the magnetic potential due to a bar magnet of dipole moment $\frac{M}{4}$ at the same point?

Question

Dr. Abubacker · Accepted Answer

(d) The potential at a point on the axial line due to a bar magnet is given by
$V = \frac{\mu_{0}}{4\pi} 	imes \frac{2M}{\left( d^{2} - l^{2} ight)}$
Hence, $V \propto M$(if all other quantities are remains same)
$	herefore\ \ \ \ \ \frac{V^{'}}{V} = \frac{M^{'}}{M}$
$\Longrightarrow \ \frac{V^{'}}{V} = \frac{M/4}{M} = \frac{1}{4}\ \ $
$V^{'} = V/4$

Q. The magnetic potential at a point on the axial line of a bar magnet of dipole moment M is V. What is the magnetic potential due to a bar magnet of dipole moment $\frac{M}{4}$ at the same point?

Explanation

Reviewed by Dr. Abubacker

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