Q. The electric field in the space between the plates of a discharge tube is $3.25 \times 10^{4}\ NC^{- 1}$. If mass of proton is 1.67$\times 10^{- 27}\ kg$ and its charge is 1.6$\times 10^{- 19}C$, the force often the proton in the field is
A) $10.4 \times 10^{- 15\ }$N
B) $2.0 \times 10^{- 23\ }$N
C) $5.40 \times 10^{- 15\ }$N
D) $5.20 \times 10^{- 15\ }$N
Explanation
(d) $F = q\ E = 1.6 \times 10^{- 19} \times 3.25 \times 10^{4}\ $
$= 5.20 \times 10^{- 15}$N
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.