Q. Eight dipoles of charges of magnitude $e$ are placed inside a cube. The total electric flux coming out of the cube will be
A) $\frac{8e}{\varepsilon_{0}}$
B) $\frac{16e}{\varepsilon_{0}}$
C) $\frac{e}{\varepsilon_{0}}$
D) Zero
Explanation
(d) $\phi = \frac{\sum_{}^{}q}{\varepsilon_{0}} = 0\ i.e.$ net charge on dipole is zero
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.