Two point charges of $20\mu C$ and $80\mu C$ are $10cm$ apart. Where will the electric field strength be zero on the line joining the charges form $20\mu C$ charge

Question

Dr. Abubacker · Accepted Answer

(c) Let neutral point be obtained at a distance $x$ from $20\ \mu C$ charge. Hence at neutral point
$\frac{20}{(x)^{2}} = \frac{80}{(10 - x)^{2}} \Rightarrow x = + 0.033\ m$

Q. Two point charges of $20\mu C$ and $80\mu C$ are $10cm$ apart. Where will the electric field strength be zero on the line joining the charges form $20\mu C$ charge

Explanation

Reviewed by Dr. Abubacker

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