Q. A regular hexagon of side $'a'$ has a charge $Q$ at each vertex. Potential at the centre of the hexagon is $\left( K = \frac{1}{4\pi\varepsilon_{0}} \right)$
A) Zero
B) $\frac{KQ}{a}Volts$
C) $12\frac{KQ}{a}$
D) $6\frac{KQ}{a}$
Explanation
(d) $V = 6 \times \left\lbrack \frac{1}{4\pi\varepsilon_{0}} \times \frac{Q}{a} \right\rbrack$
$V = 6 \times \frac{k.Q}{a}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.