Q. The electric potential V at any point $x,\ y,\ z\ ($all the metre$)$ in space is given by $V = 4x^{2}$ volt. The electric field at the point (1m, 0, 2m) in $Vm^{- 1}$ is

A) $- 8\widehat{\dot{i}}$
B) $+ 8\widehat{\dot{i}}$
C) $- 16\widehat{\dot{i}}$
D) $16\widehat{k}$
Explanation

(a) $\because\ \ \ V = 4x^{\begin{array}{r}
2 \\
\
\end{array}}$
Hence,$\ \ \overrightarrow{E}$ $= - \frac{dV}{dr} = - 8x\widehat{\dot{i}}\ $
Hence, value of $\overrightarrow{E}$ at (1m, 0, 2m) will be
$\overrightarrow{E}$ $= - 8 \times 1\widehat{\dot{i}} = - 8\widehat{\dot{i}}\ Vm^{- 1}\ $

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.