(a) $\because\ \ \ V = 4x^{\begin{array}{r}
2 \\
\
\end{array}}$
Hence,$\ \ \overrightarrow{E}$ $= - \frac{dV}{dr} = - 8x\widehat{\dot{i}}\ $
Hence, value of $\overrightarrow{E}$ at (1m, 0, 2m) will be
$\overrightarrow{E}$ $= - 8 \times 1\widehat{\dot{i}} = - 8\widehat{\dot{i}}\ Vm^{- 1}\ $