(c) 6$\ \mu F$ and 3$\ \mu F$ capacitors are in series
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \frac{1}{C_{1}} = \frac{1}{6} + \frac{1}{3}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ C_{1} = 2$
$C_{1}\ is\ parallel\ to\ 2\ \mu F\ capacitor$
$\therefore\ \ \ \ \ \ \ \ \ \ \ \ \ \ C_{eq} = 2 + 2 = 4\mu F\ $
Total energy, $U = \frac{1}{2}CV^{2}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = \frac{1}{2} \times 4 \times (2)^{2} = 8\mu J$