Q. Two plates are 20 cm apart and the potential difference between them is 10 V. The electric field between the plates is
A) $50{\ Vm}^{- 1}$
B) $500\ {Vm}^{- 1}$
C) $0.5\ {Vm}^{- 1}$
D) $20{\ Vm}^{- 1}$
Explanation
(a) Potential gradient relates with electric field according to the relation,$E = - \frac{dV}{dr}$
$\ = - \frac{10}{20 \times 10^{- 2}} = 50\ {Vm}^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.