Find the potential at the centre of a square of side $\sqrt{2}$m. Which carries at its four corners charges $q_{1} = 3 imes 10^{- 6}C$,$q_{2} = - 3 imes 10^{- 6}C,q_{3}$=$- 4 imes 10^{- 6}C,\ q_{4} = 7 imes 10^{- 6}C$

Question

Find the potential at the centre of a square of side $\sqrt{2}$m. Which carries at its four corners charges $q_{1} = 3 	imes 10^{- 6}C$,$q_{2} = - 3 	imes 10^{- 6}C,q_{3}$=$- 4 	imes 10^{- 6}C,\ q_{4} = 7 	imes 10^{- 6}C$

Dr. Abubacker · Accepted Answer

(a) The potential
$V = \frac{1}{4\pi\varepsilon_{0}}\frac{1}{r}\left( q_{1} + q_{2} + q_{3} + q_{4} ight)$
$V = \left( 9 	imes 10^{9} ight)\left( \frac{1}{1m} ight)\left\{ (3 - 3 - 4 + 7) 	imes 10^{- 6}C ight\}$
$= 2.7 	imes 10^{4}\frac{N - m}{C}$
$= 2.7 	imes 10^{4}JC^{- 1}$
$= 2.7 	imes 10^{4}V$

Q. Find the potential at the centre of a square of side $\sqrt{2}$m. Which carries at its four corners charges $q_{1} = 3 \times 10^{- 6}C$,$q_{2} = - 3 \times 10^{- 6}C,q_{3}$=$- 4 \times 10^{- 6}C,\ q_{4} = 7 \times 10^{- 6}C$

Explanation

Reviewed by Dr. Abubacker

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