Q. A capacitor is charged to store an energy $U.$ the charging battery is disconnected. An identical capacitor is now connected to the first capacitor in parallel. The energy in each of the capacitor is
A) 3$\ U/2$
B) $U$
C) $U/4$
D) $U/2$
Explanation
(c) As battery is disconnected, total charge $Q$ is shared equally by two capacitors. energy of each capacitor
$= \frac{{(Q/2)}^{2}}{2C} = \frac{1}{4}\frac{\ Q^{2}}{\ 2C} = \frac{1}{4}U$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.