A 500 $\mu F$ capacitor is charged at a steady rate of 100$\mu{Cs}^{- 1}.$ The potential difference across the capacitor will be 10 V after in interval of

Question

Dr. Abubacker · Accepted Answer

(d) Given that,
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ C = 500\mu F$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \frac{dq}{dt} = 100\ \mu{Cs}^{- 1}\ \ $
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ V = 10$ volt
Then the total charge on the capacitor
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ q = CV$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  = 500 	imes 10^{- 6} 	imes 10$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  = 5 	imes 10^{- 3}C$
Hence, time = $\frac{total\ charge}{charge\ rate\ }$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ E\ \  = \ \frac{5 	imes 10^{- 3}C}{100 	imes 10^{- 6}C}s$
= 50s

Q. A 500 $\mu F$ capacitor is charged at a steady rate of 100$\mu{Cs}^{- 1}.$ The potential difference across the capacitor will be 10 V after in interval of

Explanation

Reviewed by Dr. Abubacker

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