Q. Potential energy of two equal negative point charges 2$\mu$C each held 1 m apart in air is
A) 2 J
B) 2 eV
C) 4 J
D) 0.036 J
Explanation
(d) PE$\ = \frac{q_{1}q_{2}}{4\pi\varepsilon_{0}r} = \frac{9 \times 10^{9}\left( 2 \times 10^{- 6} \right)^{2}}{1} = 0.036\ J$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.